5[m+1]+6=3[4+m]+2m-1

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Solution for 5[m+1]+6=3[4+m]+2m-1 equation: 


Simplifying
5[m + 1] + 6 = 3[4 + m] + 2m + -1

Reorder the terms:
5[1 + m] + 6 = 3[4 + m] + 2m + -1
[1 * 5 + m * 5] + 6 = 3[4 + m] + 2m + -1
[5 + 5m] + 6 = 3[4 + m] + 2m + -1

Reorder the terms:
5 + 6 + 5m = 3[4 + m] + 2m + -1

Combine like terms: 5 + 6 = 11
11 + 5m = 3[4 + m] + 2m + -1
11 + 5m = [4 * 3 + m * 3] + 2m + -1
11 + 5m = [12 + 3m] + 2m + -1

Reorder the terms:
11 + 5m = 12 + -1 + 3m + 2m

Combine like terms: 12 + -1 = 11
11 + 5m = 11 + 3m + 2m

Combine like terms: 3m + 2m = 5m
11 + 5m = 11 + 5m

Add '-11' to each side of the equation.
11 + -11 + 5m = 11 + -11 + 5m

Combine like terms: 11 + -11 = 0
0 + 5m = 11 + -11 + 5m
5m = 11 + -11 + 5m

Combine like terms: 11 + -11 = 0
5m = 0 + 5m
5m = 5m

Add '-5m' to each side of the equation.
5m + -5m = 5m + -5m

Combine like terms: 5m + -5m = 0
0 = 5m + -5m

Combine like terms: 5m + -5m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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